Find the cube-roots of 3375 x 512
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Prime factors of 3375:
Prime factors of 512:
3375×5123=33753×5123=(3×3×3)×(5×5×5)3×(2×2×2)×(2×2×2)×(2×2×2)3=(3×5)×(2×2×2)=(15)×(8)=120\sqrt[3]{3375 \times 512}\\[1em] = \sqrt[3]{3375}\times{\sqrt[3]{512}}\\[1em] = \sqrt[3]{(3 \times 3 \times 3)\times(5 \times 5 \times 5)}\times{\sqrt[3]{(2 \times 2 \times 2)\times (2 \times 2 \times 2) \times (2 \times 2 \times 2)}}\\[1em] = (3 \times 5)\times(2 \times 2 \times 2)\\[1em] = (15)\times(8)\\[1em] = 12033375×512=33375×3512=3(3×3×3)×(5×5×5)×3(2×2×2)×(2×2×2)×(2×2×2)=(3×5)×(2×2×2)=(15)×(8)=120
Hence, 3375×5123=120\sqrt[3]{3375 \times 512} = 12033375×512=120
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