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Mathematics

Find the coordinates of the images of the following points under reflection in the origin :

(i) (2, -5)

(ii) (32,12)\Big(-\dfrac{3}{2}, -\dfrac{1}{2}\Big)

(iii) (0, 0).

Reflection

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Answer

(i) We know that,

Rules to find the reflection of a point in the origin :

  1. Change the sign of abscissa i.e. x-coordinate.
  2. Change the sign of ordinate i.e. y-coordinate.

∴ Point P'(-2, 5) is the image on reflection.

Hence, (-2, 5) is the image of the point (2, -5) on reflection in origin.

(ii) We know that,

Rules to find the reflection of a point in the origin :

  1. Change the sign of abscissa i.e. x-coordinate.
  2. Change the sign of ordinate i.e. y-coordinate.

∴ Point P'(32,12)(\dfrac{3}{2}, \dfrac{1}{2}) is the image on reflection.

Hence, (32,12)(\dfrac{3}{2}, \dfrac{1}{2}) is the image of the point (32,12)(-\dfrac{3}{2}, -\dfrac{1}{2}) on reflection in origin.

(iii) We know that,

Rules to find the reflection of a point in the origin :

  1. Change the sign of abscissa i.e. x-coordinate.
  2. Change the sign of ordinate i.e. y-coordinate.

∴ Point P'(0, 0) is the image on reflection.

Hence, (0, 0) is the image of the point (0, 0) on reflection in origin.

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