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Mathematics

Find the coordinates of the centroid of a triangle whose vertices are :

A(-1, 3), B(1, -1) and C(5, 1).

Section Formula

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Answer

Coordinates of the centroid of the triangle whose vertices are (x1, y1), (x2, y2) and (x3, y3) is given by

(x1+x2+x33,y1+y2+y33)\Big(\dfrac{x1 + x2 + x3}{3}, \dfrac{y1 + y2 + y3}{3}\Big)

Putting values in the formula we get,

=(1+1+53,3+(1)+13)=(53,33)=(53,1).= \Big(\dfrac{-1 + 1 + 5}{3}, \dfrac{3 + (-1) + 1}{3}\Big) \\[1em] = \Big(\dfrac{5}{3}, \dfrac{3}{3}\Big) \\[1em] = \Big(\dfrac{5}{3}, 1\Big).

Hence, the coordinates of the centroid of the triangle are (53,1)\Big(\dfrac{5}{3}, 1\Big).

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