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Chemistry

Find the:

(a) number of molecules in 73 g of HCl,

(b) weight of 0.5 mole of O2,

(c) number of molecules in 1.8 g of H2O,

(d) number of moles in 10 g of CaCO3,

(e) weight of 0.2 mole of H2 gas,

(f) number of molecules in 3.2 g of SO2.

Mole Concept

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Answer

(a) Number of molecules in 73 g of HCl —

Molecular wt. of any substance contain 6.022 × 1023 molecules.

Mass of 1 mole of HCl is 1 + 35.5 = 36.5 g

36.5 g of HCl contains 6.022 × 1023 molecules

∴ 73 g of HCl contains 6.022×1023×7336.5\dfrac{6.022 \times 10^{23} \times 73 }{36.5}

= 1.2 × 1024 molecules

(b) Weight of 0.5 mole of O2

1 mole of O2 weighs = 2O = 2 x 16 = 32 g

∴ 0.5 moles will weigh = 322\dfrac{32}{2} = 16 g

(c) Number of molecules in 1.8 g of H2O —

Molecular wt. of any substance contains 6.022 × 1023 molecules.

Mass of 1 mole of H2O is (2 x 1) + 16 = 2 + 16 = 18 g

18 g of H2O contains 6.022 × 1023 molecules

∴ 1.8 g of H2O contains 6.022×1023×1.818\dfrac{6.022 \times 10^{23} \times 1.8 }{18}

= 6.02 × 1022 molecules

(d) Number of moles in 10 g of CaCO3

Mass of 1 mole of CaCO3 = 40 + 12 + 3(16) = 52 + 48 = 100 g

100 g of CaCO3 = 1 mole

∴ 10 g of CaCO3 = 1×10100\dfrac{1 \times 10}{100}

= 0.1 mole

(e) Weight of 0.2 mole H2 gas —

1 mole of H2 weighs = 2 g

∴ 0.2 moles will weigh = 2×0.21\dfrac{2 \times 0.2}{1} = 0.4 g

(f) No. of molecules in 3.2 g of SO2

Molecular wt. of any substance contain 6 × 1023 molecules.

Mass of 1 mole of SO2 is 32 + 2(16) = 32 + 32 = 64 g

64 g of SO2 contains 6 × 1023 molecules

∴ 3.2 g of SO2 contains 6×1023×3.264\dfrac{6 \times 10^{23} \times 3.2 }{64}

= 3 x 1022 molecules.

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