Find the equations of the lines, whose :

(i) slope = - 4 and y-intercept = 2

(ii) slope = 0 and y-intercept = -5

(iii) slope = 3 and y-intercept = 4

(iv) slope = 1 and y-intercept = -5.

(i) slope = - 4 ⇒ m = -4

y-intercept = 2 ⇒ c = 2

Equation is : y = mx + c, where m is slope and c is y-intercept.

⇒ y = (-4)x + 2

⇒ y = -4x + 2

Hence, the equation of line is y = -4x + 2.

(ii) slope = 0 ⇒ m = 0

y-intercept = -5 ⇒ c = -5

Equation is : y = mx + c, where m is slope and c is y-intercept.

⇒ y = 0 $\times$ x - 5

⇒ y = - 5

⇒ y + 5 = 0

Hence, the equation of line is y + 5 = 0.

(iii) slope = 3 ⇒ m = 3

y-intercept = 4 ⇒ c = 4

Equation is : y = mx + c, where m is slope and c is y-intercept.

⇒ y = 3x + 4

Hence, the equation of line is y = 3x + 4.

(iv) slope = 1 ⇒ m = 1

y-intercept = -5 ⇒ c = -5

Equation is : y = mx + c, where m is slope and c is y-intercept.

⇒ y = x - 5

Hence, the equation of line is y = x - 5.