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Mathematics

Find the distance between the points (2, -5) and (7, 7).

Coordinate Geometry

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Answer

Distance between 2 points (x1, y1) and (x2, y2) = (x2−x1)2+(y2−y1)2\sqrt{(x2 - x1)^2 + (y2 - y1)^2}

Distance between (2,-5) and (7, 7) =

=(7−2)2+(7−(−5))2=52+(7+5)2=52+122=25+144=169=13= \sqrt{(7 - 2)^2 + (7 - (-5))^2}\\[1em] = \sqrt{5^2 + (7 + 5)^2}\\[1em] = \sqrt{5^2 + 12^2}\\[1em] = \sqrt{25 + 144}\\[1em] = \sqrt{169}\\[1em] = 13

Hence, the distance between the points (2,-5) and (7, 7) = 13 units.

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