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Mathematics

Find a G.P. for which the sum of first two terms is -4 and the fifth term is 4 times the third term.

GP

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Answer

Given,

⇒ a + a2 = -4

⇒ a + ar = -4

⇒ a(1 + r) = -4 ……..(i)

⇒ a5 = 4a3

⇒ ar4 = 4ar2

⇒ r2 = 4

⇒ r = ± 2

Let r = 2.

Substituting value of r in (i) we get,

⇒ a(1 + 2) = -4

⇒ 3a = -4

⇒ a = 43-\dfrac{4}{3}.

G.P. = a, ar, ar2, ……..

= 43,83,163-\dfrac{4}{3}, -\dfrac{8}{3}, -\dfrac{16}{3}……..

Let r = -2.

Substituting value of r in (i) we get,

⇒ a(1 + (-2)) = -4

⇒ -a = -4

⇒ a = 4.

G.P. = a, ar, ar2, ……..

= 4, -8, 16, -32,……..

Hence, G.P. = 43,83,163-\dfrac{4}{3}, -\dfrac{8}{3}, -\dfrac{16}{3}…….. or 4, -8, 16, -32.

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