Factorise :
x2−8xx^2 - \dfrac{8}{x}x2−x8
3 Likes
x2−8x=x3−23x=(x−2)(x2+x×2+22)x=1x(x−2)(x2+2x+4)x^2 - \dfrac{8}{x} = \dfrac{x^3 - 2^3}{x}\\[1em] = \dfrac{(x - 2)(x^2 + x \times 2 + 2^2)}{x}\\[1em] = \dfrac{1}{x}(x - 2)(x^2 + 2x + 4)x2−x8=xx3−23=x(x−2)(x2+x×2+22)=x1(x−2)(x2+2x+4)
Hence, x2−8x=1x(x−2)(x2+2x+4)x^2 - \dfrac{8}{x} = \dfrac{1}{x}(x - 2)(x^2 + 2x + 4)x2−x8=x1(x−2)(x2+2x+4).
Answered By
1 Like
a2−b2−c2+2bca^2 - b^2 - c^2 + 2bca2−b2−c2+2bc
a+2b+a3+8b3a + 2b + a^3 + 8b^3a+2b+a3+8b3
a−3b+a3−27b3a - 3b + a^3 - 27b^3a−3b+a3−27b3
a2+bc−ac−b2a^2 + bc - ac - b^2a2+bc−ac−b2
