Physics
Explain how you will determine experimentally the position of centre of gravity for a triangular lamina (or a triangular piece of card board).
Answer
![Explain how you will determine experimentally the position of centre of gravity for a triangular lamina. Force, Concise Physics Class 10 Solutions.](https://cdn1.knowledgeboat.com/img/cp10/triangular-lamina-centre-gravity-circle-q8-concise-physics-icse-class-10-solutions-314x438.jpg)
To determine centre of gravity for a triangular lamina, make three fine holes a, b, c near its edges. After that, suspend it from hole a along with a plumb line. Ensure that the lamina is freely suspended. When it comes to rest, draw straight line ad along the plumb line. Repeat the experiment by suspending the lamina through hole 'b' and then through hole 'c'. This gives us two straight lines, be and cf respectively. The three lines ad, be and cf intersect each other at a common point G. This common point G is the position of the centre of gravity of triangular lamina.
Related Questions
A uniform flat circular rim is balanced on a sharp vertical nail by supporting it at a point A, as shown in figure. Mark the position of centre of gravity of the rim in the diagram by the letter G.
Figure shows three pieces of card board of uniform thickness cut into three different shapes. On each diagram draw two lines to indicate the position of centre of gravity G.
Which of the following quantities remains constant in uniform circular motion?
- Velocity
- Speed
- Acceleration
- Both velocity and speed
The direction of motion in circular motion :
- is linear
- is along the tangent at that point of the circular path
- towards the centre
- none of these