KnowledgeBoat Logo

Mathematics

Draw a line segment AB of length 7 cm. Construct the locus of a point P such that area of triangle PAB is 14 cm2.

Locus

10 Likes

Answer

Let the height of triangle PAB = h cm.

So, area of triangle = 12\dfrac{1}{2} × base × height

⇒14=12×7×h⇒14×27=h⇒h=287⇒h=4cm\Rightarrow 14 = \dfrac{1}{2} \times 7 \times h \\[1em] \Rightarrow \dfrac{14 \times 2}{7} = h \\[1em] \Rightarrow h = \dfrac{28}{7} \\[1em] \Rightarrow h = 4 \text{cm}

Draw a line segment AB of length 7 cm. Construct the locus of a point P such that area of triangle PAB is 14 cm2. Locus, ML Aggarwal Understanding Mathematics Solutions ICSE Class 10.

Hence, the locus of point P will be a pair of straight lines (CD and EF in figure) at a distance of 4 cm from AB.

Answered By

2 Likes

Related Questions