Chemistry
Distinguish between the following pairs of compounds using the reagent given in the bracket:
Dilute hydrochloric acid and dilute sulphuric acid [using lead nitrate soln.]
Answer
Sulphuric acid forms a white precipitate with lead nitrate solution. This precipitate does not dissolve on warming the reaction mixture.
H2SO4 (dil.) + Pb(NO3)2 ⟶ 2HNO3 + PbSO4 ↓ [white ppt. formed which does not dissolve on warming the mixture].
Hydrochloric acid forms a white precipitate with lead nitrate solution. This precipitate dissolves on warming the reaction mixture so as to form clear solution.
2HCl (dil.) + Pb(NO3)2 ⟶ 2HNO3 + PbCl2 ↓ [white ppt. formed which dissolves on warming the mixture].
Hence, dilute hydrochloric acid and dilute sulphuric acid can be distinguished using lead nitrate solution.
Related Questions
State which property of sulphuric acid is shown by the reaction of concentrated sulphuric acid with:
(i) Ethanol
(ii) Carbon
Write balanced chemical equations for the following reactions:
Action of dilute sulphuric acid on —
(i) Sodium hydroxide
(ii) Zinc sulphide
Complete the following equation:
C + conc. H2SO4 ⟶
Copy and complete the following table which refers to the industrial method for preparation of sulphuric acid.
Name of the compound Name of the process Catalytic equation [with the catalyst] Sulphuric acid