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Mathematics

The distance between the points (7, -5) and (3, -1) is :

  1. 4 units

  2. 3 units

  3. 424{\sqrt2} units

  4. 5 units

Distance Formula

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Answer

Let (7, -5) = (x1, y1) and (3, -1) = (x2, y2)

Distance between the given points =

(x2x1)2+(y2y1)2=(37)2+((1)(5))2=(4)2+(4)2=16+16=32=42units\sqrt{(x2 - x1)^2 + (y2 - y1)^2}\\[1em] = \sqrt{(3 - 7)^2 + ((-1) - (-5))^2}\\[1em] = \sqrt{(-4)^2 + (4)^2}\\[1em] = \sqrt{16 + 16}\\[1em] = \sqrt{32}\\[1em] = 4{\sqrt2} \text{units}

Hence, option 3 is the correct option.

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