Computer Applications
Determine the output of the following program.
public class PredictOutput3
{
public static void main(String args[])
{
int a = 2, b = 2, c = 2;
System.out.println("Output 1: " + (a + 2 < b * c));
System.out.println("Output 2: " + (a + 2 < (b * c)));
}
}
Answer
Output
Output 1: false
Output 2: false
Explanation
In the first println statement, the expression is (a + 2 < b * c). b * c is evaluated first as * has higher precedence than + and <. After that a + 2 is evaluated as between + and <, + has higher precedence. Comparison is done in the end. As 4 < 4 is false so false is printed. The case of second println statement is similar.
Related Questions
Determine the output of the following program.
public class PredictOutput2 { public static void main(String args[]) { int a = 6, b = 2, c = 3; System.out.println("Output 1: " + (a == b * c)); System.out.println("Output 2: " + (a == (b * c))); } }What is the difference between the following two statements in terms of execution? Explain the results.
x -= 5;
x =- 5;What is concatenation? On which data type is concatenation performed?
Determine the output of the following program.
public class PredictOutput1 { public static void main(String args[]) { int a = 4, b = 2, c = 3; System.out.println("Output 1: " + (a = b * c)); System.out.println("Output 2: " + (a = (b * c))); } }