Define the term Mole. A gas cylinder contains 24 × 10 24 molecules of nitrogen gas. If Avogadro's number is 6 × 10 23 and the relative atomic mass of nitrogen is 14, calculate : (i) Mass of nitrogen gas in the cylinder. (ii) Volume of nitrogen at STP in dm 3

Mole A mole is the amount of substance which contains the same number of units as the number of atoms in 12,000 g of carbon - 12 [ 6 C 12 ] (i) Gram molecular mass of N 2 = 2(14) = 28 g 6 × 10 23 molecules of N 2 weighs 28 g 24 × 10 24 molecules will weigh x 24 × 10 24 = 1120 g (ii) 6 × 10 23 molecules of N 2 occupies 22.4 dm 3 24 × 10 24 molecules of N 2 will occupy x 24 × 10 24 = 896 dm 3 Hence, Mass of nitrogen gas = 1120 g and vol. occupied is 896 dm 3

Chemistry

Define the term Mole.
A gas cylinder contains 24 × 10²⁴ molecules of nitrogen gas. If Avogadro's number is 6 × 10²³ and the relative atomic mass of nitrogen is 14, calculate :
(i) Mass of nitrogen gas in the cylinder.
(ii) Volume of nitrogen at STP in dm³

Stoichiometry

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Chemistry

Define the term Mole.A gas cylinder contains 24 × 1024 molecules of nitrogen gas. If Avogadro's number is 6 × 1023 and the relative atomic mass of nitrogen is 14, calculate :(i) Mass of nitrogen gas in the cylinder.(ii) Volume of nitrogen at STP in dm3

Stoichiometry

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Define the term Mole.
A gas cylinder contains 24 × 10²⁴ molecules of nitrogen gas. If Avogadro's number is 6 × 10²³ and the relative atomic mass of nitrogen is 14, calculate :
(i) Mass of nitrogen gas in the cylinder.
(ii) Volume of nitrogen at STP in dm³

Calculate the no. of moles and the no. of molecules present in 1.4 g of ethylene gas (C₂H₄). What is the vol. occupied by the same amount of C₂H₄. State the vapour density of C₂H₄.
(Avog. No. = 6 × 10²³ ; C = 12, H = 1]

Gas 'X' occupies a volume of 100 cm³ at S.T.P and weighs 0.5 g. Find it's relative molecular mass.