Mathematics
Construct triangle ABC, with AB = 7 cm, BC = 8 cm and ∠ABC = 60°. Locate by construction the point P such that :
(i) P is equidistant from B and C and
(ii) P is equidistant from AB and BC.
(iii) Measure and record the length of PB.
Locus
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Answer
Construct the △ABC with the given data:
(i) Since, P is equidistant from B and C hence, it will be a point on the perpendicular bisector of BC i.e. YZ.
(ii) Since, P is also equidistant from AB and BC, so, it will be a point on angle bisector of B i.e. BX.
Hence, the intersection of BX and YZ is point P.
(iii) The length of PB is 4.6 cm.
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Using ruler and compasses, construct
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(i) Construct △ABC, where AB = 3.5 cm, BC = 6 cm and ∠ABC = 60°.
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(iv) Mark the point P which is equidistant from AB, BC and also equidistant from B and C. Measure and record the length of PB.