Mathematics
Construct a rhombus whose diagonals are 4.7 cm and 5.4 cm.
Rectilinear Figures
3 Likes
Answer
Steps of construction:
Draw AC = 4.7 cm.
Draw perpendicular bisector to AC which cuts AC at O.
From this perpendicular, cut OD and OB such that, OD = OB = x BD = x 5.4 cm = 2.7 cm.
Join AB, BC, CD and DA.
Hence, ABCD is the required rhombus.
Answered By
2 Likes
Related Questions
ABCD is a parallelogram. If AB = 2AD and P is the mid-point of CD; prove that : ∠APB = 90°.
Construct a parallelogram ABCD in which diagonal AC = 6.3 cm; diagonal BD = 7cm and the acute angles between the diagonals is 45°.
In a parallelogram ABCD, P is a point on side AD such that 3AP = AD and Q is a point on BC such that 3CQ = BC. Prove that : AQCP is a parallelogram.
The following figure shows a parallelogram ABCD.
Use the given informations to find the values of x, y and z.
