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Physics

Complete the following —

(a) 1 kWh=1 volt×1 ampere×……1000(b) 1 kWh=…… J\text{(a) 1 kWh} = \dfrac{1 \text{ volt} \times 1 \text{ ampere} \times \text{……} }{1000} \\[2em] \text{(b) 1 kWh} = \text{…… J}

Current Electricity

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Answer

(a) 1 kWh=1 volt×1 ampere×1 hour1000(b) 1 kWh=3.6×106J\text{(a) 1 kWh} = \dfrac{1 \text{ volt} \times 1 \text{ ampere} \times \boldsymbol{1 \space hour} }{1000} \\[2em] \text{(b) 1 kWh} = \boldsymbol{3.6 \times 10^6 J}

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