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Mathematics

Classify the following numbers as rational or irrational:

(i)23(ii)225(iii)0.3796(iv)7.478478…(v)1.101001000100001…(vi)345.0456\begin{matrix} \text{(i)} & \sqrt{23} \\[1.5em] \text{(ii)} & \sqrt{225} \\[1.5em] \text{(iii)} & 0.3796 \\[1.5em] \text{(iv)} & 7.478478… \\[1.5em] \text{(v)} & 1.101001000100001… \\[1.5em] \text{(vi)} & 345.0\overline{456} \\[1.5em] \end{matrix}

Rational Irrational Nos

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Answer

Rational numbers are in the form c, q ≠ 0, and p and q are integers.

(i) 23\bold{\sqrt{23}} is an irrational number , as it is not a perfect square so it cannot be written in the form pq\dfrac{p}{q} , q ≠ 0.

(ii) 225\sqrt{225} = 15×15\sqrt{15×15} = 15 = 151\dfrac{15}{1},

As it can be written in the form pq\dfrac{p}{q} , q ≠ 0.

225\bold{\sqrt{225}} is a rational number .

(iii) 0.3796 = 37961000\dfrac{3796}{1000}

Since, the decimal expansion is terminating decimal.

∴ 0.3796 is a rational number .

(iv) 7.478478

Let x = 7.478478 ….(i)\text{….(i)}

Since there is three repeating digit after decimal point,

Multiplying both sides by 1000, we get

1000x = 7478.478478… ….(ii)\text{….(ii)}

Subtracting (i) from (ii) we get,

999x = 7471

x = 7471999\bold{\dfrac{7471}{999}}

∴ It is non terminating , repeating rational number .

(v) 1.101001000100001…

Since number of 0's are increasing between two consecutive terms as we move further , So it is non terminating, non repeating decimal.

∴ 1.101001000100001… is an irrational number.

(vi) 345.0456345.0\overline{456}

345.0456345.0\overline{456} = 345.0456456…

Let x = 345.0456456…

Multiply both sides by 10, we get

10x = 3450.456456.. ….(i)\text{….(i)}

Since, after decimal there are three repeating digit:

Multiply both sides by 1000, we get

10000x = 3450456.456456… ….(ii)\text{….(ii)}

Subtracting (i) from (ii) ,

9990x = 3447006

x = 34470069990\bold{\dfrac{3447006}{9990}}

since, it is non-terminating , repeating decimal.

345.0456\bold{345.0\overline{456}} is a Rational number .

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