A circle is inscribed in a square of side 14 cm. Find the area enclosed between the square and the circle.

Area of square = side²

= 14²

= 196 cm²

Since the circle is inscribed in the square, its diameter is equal to the side length of the square, which is 14 cm. The radius (r) is half of the diameter:

r = $\dfrac{14}{2}$ = 7 cm

Area of circle = πr²

= π x 7²

= $\dfrac{22}{7}$ x 49

= 154 cm²

Area enclosed between the square and the circle = Area of square - Area of circle

= 196 cm² - 154 cm²

= 42 cm²

Hence, the area enclosed between the square and the circle is 42 cm².