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Mathematics

Choose the correct choice in the following and justify :

11th term of the A.P. : -3, 12-\dfrac{1}{2}, 2, ….., is

  1. 28

  2. 22

  3. -38

  4. 4812-48\dfrac{1}{2}

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Answer

Given,

A.P. : -3, 12-\dfrac{1}{2}, 2, …..,

First term (a) = -3 and common difference (d) = 12(3)=12+3=212-\dfrac{1}{2} - (-3) = -\dfrac{1}{2} + 3 = 2\dfrac{1}{2} = 2.5

By formula,

an = a + (n - 1)d

Substituting values we get :

a11 = -3 + (11 - 1) × 2.5

= -3 + 10 × 2.5

= -3 + 25

= 22.

Hence, Option 2 is the correct option.

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