Chemistry
Calculate the percentage of platinum in ammonium chloroplatinate (NH4)2 PtCl6
(Give your answer correct to the nearest whole number.
[N = 14, H = 1, Cl = 35.5, Pt = 195]
Stoichiometry
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Answer
Molecular weight of ammonium chloroplatinate (NH4)2PtCl6
= 2[14 + 4(1)] + 195 + 6(35.5)
= 2[18] + 195 + 213
= 444 g
444 g of ammonium chloroplatinate contains 195 g of Pt
∴ 100 g of ammonium chloroplatinate will contain = x 100 = 43.91% = 44%
Hence, 44% percentage of platinum is present in ammonium chloroplatinate
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