Chemistry
Calculate the % of boron [B] in borax Na2B4O7.10H2O.
[H = 1, B = 11, O = 16, Na = 23]
Stoichiometry
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Answer
Molecular weight of borax Na2B4O7.10H2O
= 2(23) + 4(11) + 7(16) + 10[2(1)+ 16]
= 46 + 44 + 112 + 180 = 382 g
382 g of borax contains 44 g of boron
∴ 100 g of borax will contain = x 100 = 11.5%
Hence, Percentage of boron is 11.5%
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