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Mathematics

Calculate the mean, the median and the mode of the following distribution :

Age in yearsNo. of students
122
133
145
156
164
173
182

Measures of Central Tendency

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Answer

We construct the table as under :

Age in years (xi)No. of students (fi)Cumulative frequencyfixi
122224
133539
1451070
1561690
1642064
1732351
1822536
Total25374

Mean = ΣfixiΣfi=37425\dfrac{Σfixi}{Σf_i} = \dfrac{374}{25} = 14.96

Here, n (no. of observations) = 25, which is odd

Median=n+12th observation=25+12=262=13th observation.\therefore \text{Median} = \dfrac{n + 1}{2} \text{th observation} \\[1em] = \dfrac{25 + 1}{2} \\[1em] = \dfrac{26}{2} \\[1em] = 13 \text{th observation}.

The age of observation from 11th to 16th = 15.

∴ Median = 15.

Highest no. of students are 15 years old.

∴ Mode = 15.

Hence, mean = 14.96, median = 15 and mode = 15.

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