Chemistry
Calculate:
(a) The mass of 12.044 x 1023 oxygen atoms.
(b) What is the vapour density of ethylene?
Mole Concept
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Answer
(a) No. of moles of oxygen atoms = = 2 moles
Mass of oxygen atoms = no. of moles x atomic mass
= 2 x 16 = 32 g.
∴ The mass of 12.044 x 1023 oxygen atoms is 32 grams.
(b) Gram molecular mass of ethylene (C2H4) = 2(12) + 4(1) = 24 + 4 = 28 g
Vapour density = = = 14
Hence, vapour density is 14
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