Calculate: (a) The gram molecular mass of chlorine if 308 cm 3 of it at S.T.P. weighs 0.979 g (b) The volume of 4 g of H 2 at 4 atmospheres. (c) The mass of oxygen in 2.2 litres of CO 2 at S.T.P.

(a) The mass of 22.4 L of a gas at S.T.P. is equal to it's gram molecular mass. 308 cm 3 of chlorine weighs 0.979 g 22,400 cm 3 of chlorine will weigh = × 22400 = 71.2 g (b) Molar mass of H 2 = 2H = 2 x 1 = 2 g 2g H 2 at 1 atm has volume = 22.4 dm 3 4 g H 2 at 1 atm will have volume 2 x 22.4 = 44.8 dm 3 Now, For 4 g H 2 P 1 = 1 atm, V 1 = 44.8 dm 3 P 2 = 4 atm, V 2 = ? Using formula P 1 V 1 = P 2 V 2 (c) Molar mass of oxygen in carbon dioxide = 2O = 2 x 16 = 32 g Mass of oxygen in 22.4 litres of CO 2 = 32 g Mass of oxygen in 2.2 litres of CO 2 = x 2.2 = 3.14 g

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Chemistry

Calculate:
(a) The gram molecular mass of chlorine if 308 cm³ of it at S.T.P. weighs 0.979 g
(b) The volume of 4 g of H₂ at 4 atmospheres.
(c) The mass of oxygen in 2.2 litres of CO₂ at S.T.P.

Mole Concept

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Chemistry

Calculate:
(a) The gram molecular mass of chlorine if 308 cm³ of it at S.T.P. weighs 0.979 g
(b) The volume of 4 g of H₂ at 4 atmospheres.
(c) The mass of oxygen in 2.2 litres of CO₂ at S.T.P.

Mole Concept

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Chemistry

Calculate:(a) The gram molecular mass of chlorine if 308 cm3 of it at S.T.P. weighs 0.979 g(b) The volume of 4 g of H2 at 4 atmospheres.(c) The mass of oxygen in 2.2 litres of CO2 at S.T.P.

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Calculate:
(a) The gram molecular mass of chlorine if 308 cm³ of it at S.T.P. weighs 0.979 g
(b) The volume of 4 g of H₂ at 4 atmospheres.
(c) The mass of oxygen in 2.2 litres of CO₂ at S.T.P.

The molecular formula for elemental sulphur is S₈. In a sample of 5.12 g of sulphur:
(a) How many moles of sulphur are present?
(b) How many molecules and atoms are present?

If phosphorus is considered to contain P₄ molecules, then calculate the number of moles in 100 g of phosphorus?

A student puts his signature with graphite pencil. If the mass of carbon in the signature is 10^-12 g, calculate the number of carbon atoms in the signature.