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Mathematics

By drawing an ogive; estimate the median for the following frequency distribution :

Weight (kg)No. of boys
10 - 1511
15 - 2025
20 - 2512
25 - 305
30 - 352

Measures of Central Tendency

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Answer

Cumulative frequency distribution table :

Weight (kg)No. of boys (frequency)Cumulative frequency
10 - 151111
15 - 202536 (11 + 25)
20 - 251248 (36 + 12)
25 - 30553 (48 + 5)
30 - 35255 (53 + 2)

Here, n = 55, which is odd.

By formula,

Median = n+12 th term=55+12=562\dfrac{n + 1}{2}\text{ th term} = \dfrac{55 + 1}{2} = \dfrac{56}{2} = 28th term.

Steps of construction of ogive :

  1. Take 2 cm = 5 units on x-axis.

  2. Take 1 cm = 10 units on y-axis.

  3. Plot the point (10, 0), as ogive always starts on x-axis representing the lower limit of the first class.

  4. Plot the points (15, 11), (20, 36), (25, 48), (30, 53) and (35, 55).

  5. Join the points by a free hand curve.

  6. Draw a line parallel to x-axis from point A (frequency) = 28, touching the graph at point B. From point B draw a line parallel to y-axis touching x-axis at point C.

By drawing an ogive; estimate the median for the following frequency distribution. Measures of Central Tendency, Concise Mathematics Solutions ICSE Class 10.

From graph, C = 18.4

Hence, median = 18.4

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