Mathematics
Bisector of angle B of triangle ABC intersects side AC at point P, then point P is :
equidistant from vertices A and C
PA = PB
PB = PC
equidistant from sides AB and BC
Locus
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Answer
We know that,
The locus of a point equidistant from two intersecting lines is the bisector of the angles between the lines.
Given,
Bisector of angle B of triangle ABC intersects side AC at point P.
∴ P is equidistant from sides AB and BC.
Hence, Option 4 is the correct option.
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