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Mathematics

Below are given the probabilities A, B, C and D of an event. P(A) : 35\dfrac{3}{5}, P(B) : 1.2, P(C) : -1.2 and P(D) = 1231\dfrac{2}{3}. Which of the above values of the probabilities is possible :

  1. Event A

  2. Event B

  3. Event C

  4. Event D

Probability

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Answer

We know that,

Probability of an event cannot be negative or greater than 1.

∴ Only probability of event A is possible.

Hence, Option 1 is the correct option.

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