Physics

At sea level, the atmospheric pressure is 1.04 x 10⁵ Pa. Assuming g = 10 m s^-2 and density of air to be uniform and equal to 1.3 kg m^-3, find the height of the atmosphere.

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We know that,

pressure = h ρ g

Given,

P = 1.04 x 10⁵ Pa

g = 10 m s^-2

density of air (ρ) = 1.3 kg m^-3

Substituting the values in the formula above, we get,

$1.04 \times 10^{5} = h \times 1.3 \times 10 \\[0.5em] h = \dfrac{1.04 \times 10^{5}}{1.3 \times 10} \\[0.5em] h = 8000 \text { m} \\[0.5em]$

Hence, height of the atmosphere = 8000 m

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