At a shooting competition the scores of a competitor were as given below :

Score	No. of shots
0	0
1	3
2	6
3	4
4	7
5	5

(i) What was his modal score ?

(ii) What was his median score ?

(iii) What was his total score ?

(iv) What was his mean score ?

(i) From above table,

The score 4 has the maximum frequency.

Hence, modal score = 4.

(ii) Cumulative frequency distribution table :

Here, n = 25, which is odd.

By formula,

Median = $\dfrac{n + 1}{2}$ th term = $\dfrac{25 + 1}{2} = \dfrac{26}{2}$ = 13th term

From table, score of 10th to 13th term is 3.

Hence, median = 3.

(iii) From cumulative frequency distribution table we get,

Total score = 80.

Hence, total score = 80.

(iv) By formula,

Mean = $\dfrac{Σfx}{Σf} = \dfrac{80}{25}$ = 3.2

Hence, mean = 3.2