An organic compound has an empirical formula (CH 2 O). Its vapour density is 45. Then what will be the molecular formula of the compound?

Chemistry

4 Likes

Given,

Empirical formula = CH₂O

Hence, empirical formula mass = 12 + 2(1) + 16 = 12 + 2 + 16 = 30 g

Molecular weight = 2 x Vapour density = 2 x 45 = 90

Molecular formula = n x empirical formula

where,

n = $\dfrac{\text{molecular mass}}{\text{empirical formula mass}}$

∴ n = $\dfrac{90}{30}$ = 3

Hence, molecular formula = 3 x CH₂O = C₃H₆O₃

Therefore, the molecular formula of the compound is C₃H₆O₃

Answered By

2 Likes