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An electric oven of 2 kW power rating is operated in a domestic electric circuit (220 V) that has a current rating of 5 A. What result do you expect? Explain.

Electro-Magnetism

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Answer

The current drawn by the electric oven :

P = V x I

I = PV\dfrac{\text{P}}{\text{V}}

Substituting the values, we get,

I = 2000220\dfrac{2000}{220} = 9.09 A

The current drawn by the electric oven is 9.09 A which exceeds the 5A current rating of the circuit, hence, the fuse wire will melt and break the circuit.

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