An electric bulb of resistance 500 Ω, draws a current of 0.4 A. Calculate the power of the bulb and the potential difference at it's end.

Given,

R = 500 Ω,

I = 0.4 A

Power of bulb P = I² R
= (0.4)² x 500 = 80 W

Potential difference at the ends of the bulb V = IR = 0.4 x 500 = 200 V