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An artificial satellite is moving in a circular orbit of radius 42250 km. Calculate its speed if it takes 24 hours to revolve around the earth.

Motion in One Dimension

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Answer

Given,

Radius of the orbit (r) = 42250 km

∴ circumference of the orbit

= 2 x 227\dfrac{22}{7} x r

= 2 x 227\dfrac{22}{7} x 42250

= 265571.42 km

Time taken to complete one revolution in the orbit = 24 hours

Convert hours into sec

1 hour = 3600 sec

So, 24 hour = 24 x 3600 sec

Speed = DistanceTime\dfrac{\text{Distance}}{\text{Time}}

Substituting we get,

Speed = 265571.4224×3600\dfrac{265571.42}{24 \times 3600} = 3.07 kms-1

∴ Speed of the artificial satellite = 3.07 kms-1.

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