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Chemistry

Ammonia burns in oxygen and combustion, in the presence of a catalyst, may be represented by

2NH3 + 2 12\dfrac{1}{2} O2 ⟶ 2NO + 3H2O

[H = 1, N = 14, O = 16]

What mass of steam is produced when 1.5 g of nitrogen monoxide is formed?

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Answer

2NH3+212O22NO+3H2O2[14+16]3[2(1)+16]60 g54 g\begin{matrix} 2\text{NH}3 & + &2\dfrac{1}{2}\text{O}2 & \longrightarrow & 2\text{NO} & + &3\text{H}_2\text{O} \ &&&&2[14 + 16] && 3[2(1) + 16] \ &&&& 60 \text{ g} && 54 \text{ g} \ \end{matrix}

When 60 g NO is formed then, 54 g mass of steam is produced

∴ when 1.5 g NO is formed, mass of steam produced

= 5460\dfrac{54}{60} x 1.5 = 1.35 g

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