Mathematics
AC is a tangent to the given circle which touches the circle at point B. If ∠EBC = 45°; angle EDB is equal to :
45°
90°
125°
135°
Answer
From figure,
⇒ ∠ABE + ∠EBC = 180° [Linear pair]
⇒ ∠ABE + 45° = 180°
⇒ ∠ABE = 180° - 45° = 135°.
We know that,
The angle between a tangent and a chord through the point of contact is equal to an angle in the alternate segment.
⇒ ∠EDB = ∠ABE = 135°.
Hence, Option 4 is the correct option.
Related Questions
If ∠PAC : ∠PCA = 4 : 5, ∠P is :
40°
60°
105°
45°
In the given circle, PA is tangent and PBC is secant, PA = 8 cm and PB = 4 cm. The length of BC is :
8 cm
12 cm
16 cm
2 cm
Chords AB and CD of a circle intersect each other at point O such that OA : OC = 4 : 7. Then OB : OD is equal to :
4 : 7
5 : 4
7 : 4
4 : 5
In the given figure, O is the center of the circle, PA is tangent and PBC is secant. If ∠ABC = 60°; ∠P is :
30°
60°
120°
90°
