ABC is a right angled triangle in which ∠A = 90° and AB = AC. Find ∠B and ∠C.

Given,

AB = AC.

We know that angles opposite to equal sides of an isosceles triangle are equal.

∴ ∠B = ∠C = x°.

Sum of angles of triangle = 180°.

⇒ ∠A + ∠B + ∠C = 180°

⇒ 90° + x° + x° = 180°

⇒ 90° + 2x° = 180°

⇒ 2x° = 90°

⇒ x° = 45°.

Hence, ∠B = ∠C = 45°.