Physics

(a) Which characteristic of sound is affected due to the larger surface of a school bell?
(b) Calculate the distance covered by the Ultrasonic wave having a velocity of 1.5 kms^-1 in 14 s, when it is received after reflection by the receiver of the SONAR.

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(a) Loudness.

(b) Given,

Velocity = 1.5 kms^-1

Time = 14 sec

Distance = $\dfrac{\text{velocity} \times \text{time} }{2}$

(As the wave travels to the target and back so distance covered will be half of the distance travelled by the wave.)

Substituting values in the above formula we get,

Distance covered = $\dfrac{1.5 \times 14}{2}$

= 1.5 x 7 = 10.5 km

Hence, distance covered by the Ultrasonic wave = 10.5 km.

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