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Physics

A weight lifter lifted a load of 200 kgf to a height of 2.5 m in 5 s.

Calculate:

(i) the work done, and

(ii) the power developed by him.

Take g = 10Nkg-1

Work, Energy & Power

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Answer

Given,

mass = 200kgf

height = 2.5m

time = 5s

Force = mg
= 200 x 10 = 2000N

So, we get force is equal to 2000N

(i) Work done = F x h

W=2000×2.5=5000JW = 2000 \times 2.5 = 5000 J\\[0.5em]

Therefore, work done is 5000 J.

(ii)

Power developed=work donetimeP=50005=1000W\text{Power developed} = \dfrac{\text{work done}}{\text{time}} \\[0.5em] P = \dfrac{5000}{5} = 1000W

Therefore, power developed by the boy 1000 W.

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