A train starting from a railway station and moving with uniform acceleration attains a speed 40 kmh^-1 in 10 minutes. Find its acceleration.

Given.

Initial velocity (u) = 0

Final velocity (v) = 40 kmh^-1

Convert kmh^-1 to ms^-1 : multiply by $\dfrac{5}{18}$

40 x $\dfrac{5}{18}$ = 11.11 ms^-1

Time (t) = 10 minute

Convert min into s

1 min = 60 s

10 min = 60 x 10 = 600 s

Acceleration (a) =?

According to the first equation of motion,

v = u + at

or

a = $\dfrac{\text {v - u}}{\text{t}}$

Substituting we get,

a = $\dfrac{11.11-0}{600}$ = 0.0185 ms^-2

∴ the acceleration of the bus is 0.0185 ms^-2.