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A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of same radius. The total height of the toy is 15.5 cm. Find the total surface area of the toy.

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Answer

From figure,

A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of same radius. The total height of the toy is 15.5 cm. Find the total surface area of the toy. NCERT Class 10 Mathematics CBSE Solutions.

Height of cone (h) = 15.5 - 3.5 = 12 cm.

Radius of cone = Radius of hemisphere = r = 3.5 cm.

By formula,

Slant height (l) = r2+h2\sqrt{r^2 + h^2}

Substituting values we get :

l=(3.5)2+122=12.25+144=156.25=12.5 cm.l = \sqrt{(3.5)^2 + 12^2} \\[1em] = \sqrt{12.25 + 144} \\[1em] = \sqrt{156.25} \\[1em] = 12.5 \text{ cm}.

Total surface area of toy = Curved surface area of cone + Curved surface area of hemisphere

= πrl + 2πr2

= πr(l + 2r)

= 3.5π(12.5 + 2 × 3.5)

= 3.5π(12.5 + 7)

= 3.5×227×19.53.5 \times \dfrac{22}{7} \times 19.5

= 214.5 cm2.

Hence, total surface area of toy = 214.5 cm2.

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