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A spiral is made up of successive semicircles, with centres alternately at A and B, starting with centre at A, of radii 0.5 cm, 1.0 cm, 1.5 cm, 2.0 cm, ……. as shown in the fig. below. What is the total length of such a spiral made up of thirteen consecutive semicircles?

(Take π=227)(\text{Take } \pi = \dfrac{22}{7})

A spiral is made up of successive semicircles, with centres alternately at A and B, starting with centre at A, of radii 0.5 cm, 1.0 cm, 1.5 cm, 2.0 cm, ....... as shown in the fig. below. What is the total length of such a spiral made up of thirteen consecutive semicircles? NCERT Class 10 Mathematics CBSE Solutions.

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Answer

Circumference of semicircle = πr

Circumference of first circle = 0.5 π

Circumference of second circle = 1π = π

Circumference of third circle = 1.5π

Total length = 0.5π + π + 1.5π ……… upto 13 terms

The above list is an A.P. with first term (a) = 0.5π and common difference (d) = π - 0.5π = 0.5π

By formula,

Sum upto n terms = Sn = n2[2a+(n1)d]\dfrac{n}{2}[2a + (n - 1)d]

Substituting values we get :

S13=132[2×0.5π+(131)×0.5π]=132[π+12×0.5π]=132[π+6π]=132×7π=13×3.5π=13×3.5×227=13×0.5×22=13×11=143 cm.\Rightarrow S_{13} = \dfrac{13}{2}[2 \times 0.5π + (13 - 1) \times 0.5π] \\[1em] = \dfrac{13}{2}[π + 12 \times 0.5π] \\[1em] = \dfrac{13}{2}[π + 6π] \\[1em] = \dfrac{13}{2} \times 7π \\[1em] = 13 \times 3.5π \\[1em] = 13 \times 3.5 \times \dfrac{22}{7} \\[1em] = 13 \times 0.5 \times 22 \\[1em] = 13 \times 11 \\[1em] = 143 \text{ cm}.

Hence, total length of spiral = 143 cm.

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