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A solid sphere and a solid hemi-sphere have the same total surface area. Find the ratio between their volumes.

Mensuration

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Answer

Let radius of sphere be R cm and hemi-sphere be r cm.

Given,

Solid sphere and a solid hemi-sphere have the same total surface area.

4πR2=3πr2R2r2=3π4πR2r2=34Rr=34Rr=32.\therefore 4πR^2 = 3πr^2 \\[1em] \Rightarrow \dfrac{R^2}{r^2} = \dfrac{3π}{4π} \\[1em] \Rightarrow \dfrac{R^2}{r^2} = \dfrac{3}{4} \\[1em] \Rightarrow \dfrac{R}{r} = \sqrt{\dfrac{3}{4}} \\[1em] \Rightarrow \dfrac{R}{r} = \dfrac{\sqrt{3}}{2}.

Calculating ratio between volumes,

Vol. of sphereVol. of hemi-sphere=43πR323πr3=4πR3×32πr3×3=2×R3r3=2×(32)3=2×338=334.\dfrac{\text{Vol. of sphere}}{\text{Vol. of hemi-sphere}} = \dfrac{\dfrac{4}{3}πR^3}{\dfrac{2}{3}πr^3} \\[1em] = \dfrac{4πR^3 \times 3}{2πr^3 \times 3} \\[1em] = 2 \times \dfrac{R^3}{r^3} \\[1em] = 2 \times \Big(\dfrac{\sqrt{3}}{2}\Big)^3 \\[1em] = 2 \times \dfrac{3\sqrt{3}}{8} \\[1em] = \dfrac{3\sqrt{3}}{4}.

Hence, ratio between volumes = 33:43\sqrt{3} : 4.

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