Physics
A solid of mass 50 g at 150°C is placed in 100 g of water at 11°C, when the final temperature recorded is 20°C. Find the specific heat capacity of the solid. (Specific heat capacity of water = 4.2 J/g°C).
Calorimetry
ICSE 2017
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Answer
Given,
Mass of solid m1 = 50 g,
temperature of solid t1 = 150°C,
mass of water m2 = 100 g
temperature of water t2 = 11°C ,
temperature of mixture t = 20°C
Let specific heat capacity of the solid be c1
Heat lost by the solid Q1 = m1 c1 (t1 - t)
= 50 x c1 x (150 - 20) = 6500 c1 J
Heat gained by water = m2 c2 (t - t2 )
= 100 x 4.2 x (20 - 11) = 3780 J
If there is no loss of heat, by the principle of calorimetry
Heat lost by the solid = Heat gained by the water
6500 c1 = 3780
c1 = = 0.582 Jg-1° C-1
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