Physics
A solid of density 5000 kg m-3 weighs 0.5 kgf in air. It is completely immersed in water of density 1000 kg m-3. Calculate the apparent weight of the solid in water.
Fluids Upthrust
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Answer
(a) Upthrust = volume of the solid x density of fluid x acceleration due to gravity [Equation 1]
and
Volume = [Equation 2]
Given,
Density of the solid = 5000 kg m-3
Weight of the solid = 0.5 kgf
Density of water = 1000 kg m-3
Substituting the values in equation 2 to get volume
Volume = = 0.1 x 10-3
Substituting the values in the formula above we get,
Upthrust = 0.1 x 10-3 x 1000 x g = 0.1 kgf
apparent weight = true weight – upthrust
Substituting the values we get,
apparent weight = 0.5 - 0.1 = 0.4 kgf
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