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A ship on the surface of water sends a signal and receives it back from the submarine inside water after 4 s. Calculate the distance of the submarine from the ship. (The speed of sound in water is 1450 ms-1).

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Answer

As we know,

Speed of sound (V)=Total distance travelled (2d)time interval (t)\text {Speed of sound (V)} = \dfrac{\text{Total distance travelled (2d)}}{\text {time interval (t)}} \\[0.5em]

Total distance travelled by the sound in going and then coming back = 2d

Given,

t = 4 s

V = 1450 ms-1

Substituting the values in the formula above, we get,

1450=2d4d=1450×42d=1450×2d=2900m1450 = \dfrac{2d}{4} \\[0.5em] \Rightarrow d = \dfrac{1450 \times 4}{2} \\[0.5em] \Rightarrow d = 1450 \times 2 \\[0.5em] \Rightarrow d = 2900 m

Converting m to km

1000 m = 1 km

Therefore, 2900 m = 29001000\dfrac{2900}{1000} km = 2.9 km

Hence, distance of the submarine from the ship = 2.9 km

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