A piece of wax floats on brine. What fractions of it's volume is immersed?

Density of wax = 0.95 g cm^-3,

Density of brine = 1.1 g cm^-3

Given,

Density of wax = 0.95 g cm^-3

Density of brine = 1.1 g cm^-3

By the principle of floatation,

$\dfrac{\text {Volume of immersed part}}{\text{Total volume}} = \dfrac{\text {Density of wax}}{\text {Density of brine}} \\[1em] \therefore \dfrac{\text {Volume of immersed part}}{\text{Total volume}} = \dfrac{0.95}{1.1} \\[0.5em] = 0.86$

Hence, the piece of wax floats with 0.86^th part of it's volume immersed in brine surface.