A piece of stone of mass 113 g sinks to the bottom in water contained in a measuring cylinder and water level in cylinder rises from 30 ml to 40 ml. Calculate R.D. of stone.

Given,

Mass of stone = 113 g

Rise in the level of water is equivalent to the volume occupied by the stone

Rise in water level = 40 ml – 30 ml = 10 ml

∴ Volume occupied by the stone = 10 cm³

$\text{Mass} = \text{Density} \times \text{Volume} \\[0.5em] \Rightarrow \text{Density} = \dfrac{\text{Mass}}{\text{Volume}} \\[0.5em] = \dfrac{113}{10} \\[0.5em] = 11.3 \text { g cm}^{-3}$

Therefore, density of stone = 11.3 g cm^-3

$\text{R.D. of stone} = \dfrac{\text {Density of stone in g cm}^{-3}}{\text{1.0 g cm}^{-3}} \\[0.5em] = \dfrac{11.3}{1} \\[0.5em] = 11.3$

Hence,

Relative density of stone = 11.3