KnowledgeBoat Logo

Mathematics

A model of a ship is made to a scale of 1 : 200.

(i) If the length of the model is 4m, find the length of the ship.

(ii) If the area of the deck of the ship is 160000 m2, find the area of the deck of the model.

(iii) If the volume of the model is 200 litres, find the volume of the ship in m3.

Similarity

46 Likes

Answer

(i) Since, the model of the ship is made to the scale of 1 : 200.

∴ K (Scale factor) = 200.

Actual length of the ship = k × (the length of model) = 200 × 4 = 800 m.

Hence, the length of the ship is 800 m.

(ii) Area of the deck of the ship = k2 × (Area of the deck of the model)

Let area of deck of model be x m2.

160000=(200)2×xx=160000200×200x=4.\Rightarrow 160000 = (200)^2 \times x \\[1em] \Rightarrow x = \dfrac{160000}{200 \times 200} \\[1em] \Rightarrow x = 4.

Hence, the area of the deck of the ship is 4 m2.

(iii) Volume of the ship = k3 × (the volume of the model)

Given, volume of model = 200 litres = 2001000m3=0.2m3\dfrac{200}{1000} m^3 = 0.2 m^3.

Putting value in above equation we get,

=(200)3×0.2=8000000×0.2=1600000= (200)^3 \times 0.2 \\[1em] = 8000000 \times 0.2 \\[1em] = 1600000

Hence, the volume of the model of the ship is 1600000 m3.

Answered By

20 Likes


Related Questions