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Chemistry

A mixture of hydrogen and chlorine occupying 36 cm3 was exploded. On shaking it with water, 4 cm3 of hydrogen was left behind. Find the composition of the mixture.

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Answer

According to Gay lussac's law,

H2+Cl2⟶2HCl1 vol.:1 vol.⟶2 vol.\begin{matrix} \text{H}2 & + & \text{Cl}2 & \longrightarrow & 2\text{HCl} \\ 1 \text{ vol.} & : & 1 \text{ vol.} & \longrightarrow & 2 \text{ vol.} \\ \end{matrix}

As, 4 cm3 of hydrogen was left behind, hence, 36 - 4 = 32 cm3 of mixture of hydrogen and chlorine exploded.

As, 1 Vol. of hydrogen requires 1 Vol. of oxygen
∴ 16 cm3 hydrogen requires 16 cm3 of oxygen

∴ Mixture is 20 cm3 (i.e., 16 + 4) of hydrogen and 16 cm3 of chlorine.

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